2c^2+7c=4

Solution for 2c^2+7c=4 equation:

Simplifying
2c2 + 7c = 4

Reorder the terms:
7c + 2c2 = 4

Solving
7c + 2c2 = 4

Solving for variable 'c'.

Reorder the terms:
-4 + 7c + 2c2 = 4 + -4

Combine like terms: 4 + -4 = 0
-4 + 7c + 2c2 = 0

Factor a trinomial.
(-4 + -1c)(1 + -2c) = 0

Subproblem 1
Set the factor '(-4 + -1c)' equal to zero and attempt to solve:

Simplifying
-4 + -1c = 0

Solving
-4 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + -1c = 0 + 4

Combine like terms: -4 + 4 = 0
0 + -1c = 0 + 4
-1c = 0 + 4

Combine like terms: 0 + 4 = 4
-1c = 4

Divide each side by '-1'.
c = -4

Simplifying
c = -4
Subproblem 2
Set the factor '(1 + -2c)' equal to zero and attempt to solve:

Simplifying
1 + -2c = 0

Solving
1 + -2c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -2c = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -2c = 0 + -1
-2c = 0 + -1

Combine like terms: 0 + -1 = -1
-2c = -1

Divide each side by '-2'.
c = 0.5

Simplifying
c = 0.5
Solution
c = {-4, 0.5}